\n x = \n \n \frac{\n}{\n - \n b \n \pm \n \sqrt{\n b^{2} \n - \n 4 a c \n} \n} \n \n . \n

","type":"text"}]}]},{"type":"tableCell","attrs":{"colspan":1,"rowspan":1,"colwidth":[480.0]},"content":[{"type":"mediaSingle","attrs":{"layout":"center"},"content":[{"type":"media","attrs":{"width":259,"id":"fad78220-e6d9-441d-a54c-4c05eb675553","collection":"contentId-3079438337","type":"file","height":107}}]},{"type":"paragraph"}]}]},{"type":"tableRow","content":[{"type":"tableCell","attrs":{"colspan":1,"rowspan":1,"colwidth":[480.0]},"content":[{"type":"codeBlock","content":[{"text":"

\n \n A \n = \n \"[\"\n, \begin{matrix} \n \\ \n & \n x \n & \n & \n y \n & \n \\ \n \\ \n & \n z \n & \n & \n w \n & \n \\ \n \end{matrix}, \n\"]\" \n \n

","type":"text"}]}]},{"type":"tableCell","attrs":{"colspan":1,"rowspan":1,"colwidth":[480.0]},"content":[{"type":"mediaSingle","attrs":{"layout":"center"},"content":[{"type":"media","attrs":{"width":118,"id":"0249176f-420c-4d7e-947f-c9eed60047e6","collection":"contentId-3079438337","type":"file","height":57}}]},{"type":"paragraph"}]}]},{"type":"tableRow","content":[{"type":"tableCell","attrs":{"colspan":1,"rowspan":1,"colwidth":[480.0]},"content":[{"type":"codeBlock","content":[{"text":"

\n \n \n \n \n_{\int}^{\n} \n \frac{\n}{\n ⅆ \n x \n} \n \n \n \n \n

\n\n","type":"text"}]}]},{"type":"tableCell","attrs":{"colspan":1,"rowspan":1,"colwidth":[480.0]},"content":[{"type":"mediaSingle","attrs":{"layout":"center"},"content":[{"type":"media","attrs":{"width":95,"id":"db115441-32e6-429e-8e40-909e7da69c18","collection":"contentId-3079438337","type":"file","height":56}}]},{"type":"paragraph"}]}]}]},{"type":"heading","attrs":{"level":2},"content":[{"text":"AsciiMath","type":"text"}]},{"type":"paragraph","content":[{"text":"Support seems limited","type":"text"}]},{"type":"bulletList","content":[{"type":"listItem","content":[{"type":"paragraph","content":[{"type":"inlineCard","attrs":{"url":"http://docs.mathjax.org/en/latest/input/asciimath.html#asciimath-support"}},{"text":" ","type":"text"}]}]}]}],"version":1}

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`\sqrt{a+1\over b+1}`
`\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}`
`\Biggl(\biggl(\Bigl(\bigl((x)\bigr)\Bigr)\biggr)\Biggr)`

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